The smallest package weighed only 1/3 more than 1/2 the weight of the heaviest package. If the two packages combined weighed 100 kilograms, how much did the smaller package weigh?
Let the weight of the heaviet package = X Weight of the smallest package = X/2+(1/3*X/2) = X/2+X/6 = 2X/3 Then X+2X/3 = 100 (3X+2X)/3 = 100 5X/3 = 100 X = 300/5 = 60 Then the weight of the smallest package = 2X/3 = 2*60/3 = 40 So the weight of the smallest package is 40 Kg.