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Post your question here (Keep it simple and clear to get the best answers) Given that log4x=-3,find x. a,1/81 b. 1/64 c.64 d.81

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konrad509
I assume 4 is the base.

[tex]\log_4x=-3\\ 4^{-3}=x\\ x=\dfrac{1}{4^3}\\ x=\dfrac{1}{64}[/tex]

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