What is the specific heat of metal if its mass is 26.86g and it requires 418.6 J of heat energy to raise its temperature from 27.4 oC to 67.3°C?

Respuesta :

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The specific heat capacity is 0.364 J·°C⁻¹g⁻¹; q = mcΔT; ΔT = T₂ - T₁ = 67.3 °C - 27.4 °C = 39.9 °C; c = [tex] \frac{q}{mDT} = \frac{418.6 \text J}{28.86 g \times 39.9 \text C} [/tex] = 0.364 J·°C⁻¹·g⁻¹