NaiNai27
contestada

Look at points C and D on the graph:

What is the distance (in units) between points C and D? Round your answer to the nearest hundredth.


3.46 units
8.49 units
12.00 units
72.00 units

Look at points C and D on the graph What is the distance in units between points C and D Round your answer to the nearest hundredth 346 units 849 units 1200 uni class=

Respuesta :

TSO
[tex]\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\\\sqrt{(0-6)^2+(2-(-4))^2}\\\\\sqrt{(-6)^2+6^2}\\\\\sqrt{36+36}\\\\\sqrt{72}\\\\\boxed{8.49}[/tex]
JeanaShupp

Answer: 8.9 units


Step-by-step explanation:

From the given graph we can see the coordinates of C=(0,2)

The coordinates of D=(6,-4)

By using distance formula, we will find the distance between points C and D as:

CD=[tex]\sqrt{(x_2-x_1)^2+(y_2-y_1)2}[/tex]

[tex]=\sqrt{(6-0)^2+(-4-2)^2}\\=\sqrt{6^2+(-6)^2}\\=\sqrt{36+36}\\=\sqrt{72}=6\sqrt{2}\\=6\times1.4142=8.4852\approx8.9\text{ units}[/tex]