[tex] \frac{5}{12} [/tex] + [tex] \frac{1}{36} [/tex]

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23-09-2015
Mathematics

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[tex] \frac{5}{12} [/tex] + [tex] \frac{1}{36} [/tex]

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Exvited Exvited · Answer 1 · 2015-09-23T00:18:59+02:00

[tex] \frac{5}{12} [/tex] + [tex] \frac{1}{36} [/tex]

First, find the least common denominator (LCD) of the two denominators.
12: 12, 24, 36
36: 36
The LCD is 36.
Second, make the denominators the same as the LCD. / Your problem should look like: [tex] \frac{5x3}{12x3} [/tex] + [tex] \frac{1}{36} [/tex]
Third, simplify. The denominators are the same now. / Your problem should look like: [tex] \frac{15}{36} [/tex] + [tex] \frac{1}{36} [/tex]
Fourth, join the denominators. / Your problem should look like: [tex] \frac{15+1}{36} [/tex]
Fifth, simplify. / Your problem should look like: [tex] \frac{16}{36} [/tex]
Sixth, simplify. / Your problem should look like: [tex] \frac{4}{9} [/tex]

Answer as fraction: [tex] \frac{4}{9} [/tex]
Answer as decimal: 0.4444

TSO TSO · Answer 2 · 2015-09-23T15:37:55+02:00

TSO TSO

23-09-2015

[tex] \frac{5}{12} + \frac{1}{36} = ( \frac{5}{12} \times \frac{3}{3} ) + ( \frac{1}{36} \times \frac{1}{1} )= \frac{15}{36} + \frac{1}{36} = \frac{15+1}{36} = \frac{16}{36}= \frac{4\times 4}{9\times 4} =\boxed { \frac{4}{9} }[/tex]

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