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A car increases its speed from 9.6 meters per second to 11.2 meters per second in 4.0 seconds. the average acceleration of the car during this 4.0-second interval is answer

Respuesta :

Erudite1
In physics, acceleration is defined as the rate of change of the velocity of an object with respect to time. The S.I unit for acceleration is meter per second square [m/s^2].
Acceleration = change in velocity / time
From the question given above,
Acceleration, A =?
Initial velocity, F1 = 9.6 m/s
Final velocity, F2 = 11.2 m/s
Time, t = 4 s
A = [F2- F1] /4 = [11.2 - 9.6] / 4 
A = 1.6 / 4 = 0.4
Therefore, the average acceleration of the car is 0.4 m/s^2.

Avg Acceleration is

[tex]\rm 0.4\;m/sec^2[/tex]

Step by Step Solution :

Given :

Final Speed, v = 11.2 m/sec

Initial Speed, u = 9.6 m/sec

Time, t = 4 sec

Calculation :

We know that,

[tex]\rm Avg\;Acceleration = \dfrac{v - u }{t}[/tex]

[tex]\rm Avg \; Acceleration = \dfrac{11.2-9.6}{4}[/tex]

[tex]\rm Avg\;Acceleration =\dfrac{1.6}{4}=0.4 \;m/sec^2[/tex]

Therefore avg acceleration is

[tex]\rm 0.4\;m/sec^2[/tex]

For more information, refer the link given below

https://brainly.com/question/14100224?referrer=searchResults

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