Given: AB = 12
AC = 6
Prove: C is the midpoint of AB.

Proof:
We are given that AB = 12 and AC = 6. Applying the segment addition property, we get AC + CB = AB. Applying the substitution property, we get 6 + CB = 12. The subtraction property can be used to find CB = 6. The symmetric property shows that 6 = AC. Since CB = 6 and 6 = AC, AC = CB by the property. So, AC ≅ CB by the definition of congruent segments. Finally, C is the midpoint of AB because it divides AB into two congruent segments.

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cadencenterstage cadencenterstage · Answer 1 · 2020-10-14T18:45:31+02:00

Answer:

Pretty sure its the Transitive Property

Step-by-step explanation:

It's a dropdown on Edge so there's no A B C or D

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ProfChris1 ProfChris1 · Answer 2 · 2022-06-01T17:16:11+02:00

In order to prove that C is the midpoint of AB, we see truly that C is the midpoint of AB.

Midpoint actually refers to the middle point of a line or a segment.

When given that:

AB = 12

AC = 6

Using segment addition property: AC + CB = AB = 12

Symmetric property gives AC = 6 while Subtraction property shows that CB = 6

Thus: AC = CB.

Considering the definition of congruent segments, we can deduce here that AC ≅ CB.

So, its clear that C is actually the midpoint of AB because it divides AB into two congruent segments.

Learn more about congruency on https://brainly.com/question/2938476

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