Respuesta :
3 Rd side would be
13sq=12sq+xsq
Xsq=169-144
X=5
Cot theta = adj side/opp side= 5/12
13sq=12sq+xsq
Xsq=169-144
X=5
Cot theta = adj side/opp side= 5/12
Answer:
cot θ = [tex]\frac{5}{12}[/tex]
Step-by-step explanation:
If sin θ = [tex]\frac{12}{13}[/tex] and 'θ' is an acute angle then we have to find the value of cotθ
From the figure attached.
y² + 12² = 13² [ by Pythagoras Theorem ]
y + 144 = 169
y² = 169 - 144 = 25
y = 5
Now cot θ = [tex]\frac{base}{Height}[/tex]
= [tex]\frac{y}{12}[/tex]
= [tex]\frac{5}{12}[/tex]
Therefore, cot θ =[tex]\frac{5}{12}[/tex] is the answer.
