Respuesta :
mass of water*specific heat of water(tf-0)=-mass of water(negative)*specific heat of water(tf-100)
That should do
That should do
Given:
Mass of water = 50 g
Temperature of cold water Tc= 0 C
Temperature of hot water Th= 100 C
To determine:
Final temperature Tf of water
Explanation:
Heat (Q) absorbed or evolved by a substance is given as-
Q = mc(Tf-Ti)
m = mass
c = specific heat
Tf and Ti are the final and initial temperatures
In this case:
Heat lost by hot water = Heat gained by cold water
-mc(Tf - 100 ) = mc(Tf-0)
-Tf + 100 = Tf
2Tf = 100, i.e. Tf = 50 C
Ans: the final temperature is 50 C
