Ingrid kicks a football with an initial velocity of 12 m/s at an angle of 45 degrees relative to the ground. The horizontal component of the initial velocity to the nearest tenth is?

the vertical and horizontal components of the initial velocity can be determined by sine and cosine functions. Since it asked for the horizontal component you would use the formula "Vix= ViCosineθ" and the answer would be 8.5

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abidemiokin abidemiokin · Answer 2 · 2020-03-13T01:26:43+01:00

abidemiokin abidemiokin

13-03-2020

Answer:

8.5m/s

Explanation:

Given the initial velocity to be 12m/s at an angle of 45° to the ground. The horizontal component of the velocity can be expressed as U cos (theta) where;

U is the initial velocity of the object

theta is the angle between the initial velocity and the horizontal. Mathematically, Ux = Ucos(theta)

Ux = 12cos45°

Ux = 12×1/√2

Ux = 12×√2/2

Ux = 6√2m/s

Ux = 8.48m/s

Ux = 8.5m/s(to nearest tenth)

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