Respuesta :

we know that

the equation of the line in the point-slope form is equal to

[tex]y-y1=m(x-x1)[/tex]

we have

[tex]y+6=45(x+3)[/tex]  

so

the point is [tex](-3,-6)[/tex]

the slope is [tex]m=45[/tex]

With the slope and the point, find the second point

[tex]m=45=\frac{4.5}{0.10}[/tex]

the x-coordinate of the second point will be

[tex]-3+0.10=-2.90[/tex]

the y-coordinate of the second point will be

[tex]-6+4.5=-1.5[/tex]

the second point is [tex](-2.90,-1.5)[/tex]    

Graph the line

the answer in the attached figure


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Figure 1 (attached in the end) represents the graph of the equation [tex]y+6=45(x+3)[/tex].

Further explanation:

The point slope form of a line passing through the point [tex](x_{1},y_{1})[/tex] is as follows:

[tex]\fbox{\begin\\\ \math (y-y_{1})=m(x-x_{1})\\\end{minispace}}[/tex]

Given:

The given equation is [tex]y+6=45(x+3)[/tex].

Step 1:

First we will convert the equation [tex]y+6=45(x+3)[/tex] in point slope form as follows:

[tex]\fbox{\begin\\\ \begin{aligned}y+6&=45(x+3)\\y-(-6)&=45(x-(-3))\end{aligned}\\\end{minispace}}[/tex]  

Step 2:

Now, we will compare the equation [tex]y-(-6)&=45(x-(-3))[/tex] with the equation  [tex](y-y_{1})=m(x-x_{1})[/tex].

On comparing both the equations it is concluded that value of slope and the point [tex](x_{1},y_{1})[/tex] is as follows:

[tex]\fbox{\begin\\\ \begin{aligned}(x_{1},y_{1})&=(-3,-6)\\m&=45\end{aligned}\\\end{minispace}}[/tex]

Therefore the first coordinate of the line [tex]y+6=45(x+3)[/tex] is [tex](-3,-6)[/tex].

Here, [tex]45[/tex] is the slope of the line and [tex]129[/tex] is the [tex]y[/tex]- intercept of the line.

Step 3:

Now find the second point that satisfies the given equation [tex]y+6=45(x+3)[/tex].

Substitute [tex]x=0[/tex] in the equation [tex]y+6=45(x+3)[/tex] to obtain the value of [tex]y[/tex].

[tex]\begin{aligned}y+6&=45\times(0+3)\\y+6&=135\\y&=135-6\\y&=129\end{aligned}[/tex]

Therefore, the second coordinate is [tex](0,129)[/tex].

Step 4:

Substitute [tex]y=0[/tex] in the equation [tex]y+6=45(x+3)[/tex] to obtain the value of [tex]x[/tex].

[tex]\begin{aligned}y+6&=45\times(x+3)\\y+6&=45x+135\\45x&=-135+6\\45x&=-129\\x&=-\dfrac{129}{45}\\x&=-2.86\end{aligned}[/tex]  

Therefore, the third coordinate is [tex](-2.86,0)[/tex].

Thus, the coordinates for the line [tex]y+6=45(x+3)[/tex] are [tex](-3,-6),(0,129)\ \text{and}\ (-2.86,0)[/tex].

Step 5:  

Now plot the points [tex](-3,-6),(0,129)\ \text{and}\ (-2.86,0)[/tex] and join them to obtain the graph of teh equation [tex]y+6=45(x+3)[/tex].

Figure 1 (attached in the end) represents the graph of the equation [tex]y+6=45(x+3)[/tex].

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Answer details:

Grade: Middle school

Subject: Mathematics

Chapter: Linear equation

Keywords:  Linear equations, linear form, equation, line, slope, intercept, coordinate, solutions set, graph, curve, degree, polynomial, quadratic equation.

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