A total of 1.4 × 10⁵ Joule energy was dissipated by friction
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Further explanation
Let's recall Kinetic Energy Formula as follows:
[tex]Ek = \frac{1}{2}mv^2[/tex]
Ek = Kinetic Energy ( Joule )
m = mass of the object ( kg )
v = speed of the object ( m/s )
Let us now tackle the problem !
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Given:
mass of skier = m = 66 kg
height of trail = h = 230 m
velocity of skier = v = 11.0 m/s
Asked:
work done by friction = W = ?
Solution:
[tex]W = Ep - Ek[/tex]
[tex]W = mgh - \frac{1}{2}mv^2[/tex]
[tex]W = 66(9.8)(230) - \frac{1}{2}(66)(11.0)^2[/tex]
[tex]W = 148764 - 3993[/tex]
[tex]W = 144771[/tex]
[tex]W \approx 1.4 \times 10^5 \texttt{ Joule}[/tex]
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Conclusion:
A total of 1.4 × 10⁵ Joule energy was dissipated by friction
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Learn more
- Impacts of Gravity : https://brainly.com/question/5330244
- Effect of Earth’s Gravity on Objects : https://brainly.com/question/8844454
- The Acceleration Due To Gravity : https://brainly.com/question/4189441
- Newton's Law of Motion: https://brainly.com/question/10431582
- Example of Newton's Law: https://brainly.com/question/498822
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Answer details
Grade: High School
Subject: Physics
Chapter: Dynamics
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Keywords: Gravity , Unit , Magnitude , Attraction , Distance , Mass , Newton , Law , Gravitational , Constant
