The chemical reaction that occurs between the given substances is a neutralization reaction as shown below :
H_2SO_4 + 2KOH -> K_2SO_4 + 2H_2O
1 mol 2 mol 1 mol 2 mol
The number of moles of the given substances is calculated as shown :
Number of moles of H_2SO_4 = 25.0 mL x 0.50 M = 12.5 millimoles
Number of moles of KOH = 25.0 mL x 1.00 M = 25.0 millimoles
As 1 mol of sulfuric acid reacts with 2 mol of KOH to give 2 mol of water, 12.5 millimoles of sulfuric acid completely reacts with 25.0 millimoles of KOH to give 25.0 millimoles of water.
Total volume of the solution = 25.0 mL + 25.0 mL = 50.0 mL.
Density of water is 1 g/mL. Use this to calculate the mass of the solution.
Mass of the solution – 50.0 mL x 1 g/mL = 50.0
The specific heat of water is 4.184 J/gK. The temperature of the solution is increased from 23.5 degrees Celsius to 30.17 degrees Celsius.
The amount of heat released = 4.184 J/gK x 50.0 g x (30.17C – 23.50C) 1395 J
The amount of heat released per one mole of water formed can be calculated as shown :
The amount of heat released for formation of mole water = 1395 J / (25.0 m mol x 1mol/1000 m mol)
= 55,800 J
