Probability measures to determine the possibility of an event. In this case, the events are cars with no 4 wheels and cars with third row seats.
The probability that a randomly selected car with no 4-wheel drive has third row seats is 0.3
Let:
[tex]A \to[/tex] A car with no 4-wheel drive
[tex]B \to[/tex] A car that has third row seats
The probability that a randomly selected car with no 4-wheel drive has third row seats is represented as:
[tex]P(B|A)= \frac{n(A\ n\ B)}{n(A)}[/tex]
From the 2-way table, we have the following parameters:
[tex]n(A\ n\ B) = 12[/tex]
[tex]n(A) = 40[/tex]
So, the probability is:
[tex]P(B|A)= \frac{n(A\ n\ B)}{n(A)}[/tex]
[tex]P(B|A)= \frac{12}{40}[/tex]
[tex]P(B|A)= 0.3[/tex]
Hence, the probability that a randomly selected car with no 4-wheel drive has third row seats is 0.3
Read more about probability at:
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