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A car travels at uniform acceleration over a distance of 440.0 m. Its final velocity after 20.0 s is 33.0 m/s. What is its initial velocity?

Respuesta :

 10. Velocity = acceleration * time = 4 * 9.81 = 39.24m/s 

14. +3.0m/s (not sure) 

15. Instantaneous velocity ( not sure) 

18. s = 0.5 * (u+v) * t , where s=440, u = ?, v=33, t= 20 
u = 11m/s 

20. distance = 23 m, displacement = +1 m 

25. s = ut + 0.5*a (t^2), where s=25, u =0, a=9.8, t? 
25 = 0+ 4.9 (t^2) 
t^2 = 5.102 
t = 2.258 s 
skyluke89

Since it is a uniform accelerated motion, we can use the following SUVAT equation that relates initial velocity, final velocity, time and distance covered:

[tex]S=\frac{1}{2}(v_i +v_f)t[/tex]

where

S=440.0 m is the distance covered

vi is the initial velocity

vf=33.0 m/s is the final velocity

t=20.0 s is the time

Re-arranging the formula and substituting the data, we can find the initial velocity:

[tex]v_i = \frac{2S}{t}-v_f=\frac{2(440.0 m)}{20.0 s}-33.0 m/s=11.0 m/s[/tex]

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