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A culture of 1.08×1015 bacteria is in petri dish A. A culture of 2.7×1011 bacteria is in petri dish B.

How many times greater is the number of bacteria in petri dish A than petri dish B?

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Respuesta :

choixongdong
 1.08×10^15
------------------ = 0.4 x 10^4 = 4000
 2.7×10^11

answer
4000 times greater
JeanaShupp

Answer:The number of bacteria in petri dish A is 4000 times greater than petri dish B.


Step-by-step explanation:

Culture of bacteria in petri dish A=[tex]1.08\times10^{15}[/tex]

Culture of bacteria in petri dish B=[tex]2.7\times10^{11}[/tex]

Dividing culture of bacteria in petri dish A bu culturebacteria in petri dish B ,we get

[tex]\frac{1.08\times10^{15}}{2.7\times10^{11}}=\frac{108\times10^{15-11}}{270}\\\\=\frac{108}{270}\times10^{4}=0.4\times10^4=4000[/tex]

Therefore, the number of bacteria in petri dish A is 4000 times greater than petri dish B.

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