Respuesta :

[tex]\bf \qquad \textit{parabola vertex form}\\\\ \begin{array}{llll} \boxed{y=a(x-{{ h}})^2+{{ k}}}\\\\ x=a(y-{{ k}})^2+{{ h}} \end{array} \qquad\qquad vertex\ ({{ h}},{{ k}})\\\\ -------------------------------\\\\ y=5(x+2)^2+7\implies y=5\left[x-\left( \boxed{-2} \right) \right]^2\boxed{+7}[/tex]

Answer: (-2,7)

Step-by-step explanation: