Respuesta :

By v^2 = u^2 + 2gh 
v^2 = 0 + 2 x 9.8 x 15
v = √294
v = 17.15 m/s 

Answer:

[tex]v_f = 17.15 m/s[/tex]

Explanation:

Since the ball is dropped from the height

h = 15 m

so here initial speed of the ball is

[tex]u = 0[/tex]

acceleration of the ball due to gravity is given as

[tex]a = 9.8 m/s^2[/tex]

now the final speed of the ball is given as

[tex]v_f^2 - v_i^2 = 2 a d[/tex]

[tex]v_f^2 - 0 = 2(9.8)(15)[/tex]

[tex]v_f = 17.15 m/s[/tex]

Otras preguntas