C = [0.2R + 0.3] /A
or C = [R + 1.5] / 5A
[tex]\boxed{ \ R = 5(CA - 0.3) \ }[/tex]
In the equation, there are three variables, namely R, C, and A, and a constant -0.3.
We need solving for C from the equation.
Both sides divided by 5.
[tex]\boxed{ \ \frac{1}{5}R = CA - 0.3 \ }[/tex]
We can write ¹/₅ to 0.2.
[tex]\boxed{ \ 0.2R = CA - 0.3 \ }[/tex]
Both sides added by 0.3.
[tex]\boxed{ \ 0.2R + 0.3 = CA \ }[/tex]
[tex]\boxed{ \ CA = 0.2R + 0.3 \ }[/tex]
Finally, both sides divided by A.
As follows, the result is [tex]\boxed{\boxed{ \ C = \frac{0.2R + 0.3}{A} \ }}[/tex]
Or, if we multiply the right side by ⁵/₅ then the other form is
[tex]\boxed{\boxed{ \ C = \frac{R + 1.5}{5A} \ }}[/tex]
That's all the steps to get C as a subject.
Keywords: solve for C, R = 5(CA - 0.3), both sides, divide, add, multiply, subject, steps
