Respuesta :
8 C 3 = 8! / (3!(8 - 3)!) = 8! / (3! * 5!) = (8 * 7 * 6 * 5!) / (3! * 5!) = (8 * 7 * 6) / (6) = 56
56 choices.
56 choices.
Answer: 56
Step-by-step explanation:
Given: An astronomer wishes to measure on a photograph the distance between the image of a certain star and three other star images nearby.
The total number of images nearby = 8
The number of images chosen by astronomer = 3
Then, the number of choices of the three stars without being in order is given by :-
[tex]^8C_3=\frac{8!}{3!(8-3)!}=\frac{8\times7\times6\times5!}{3!5!}=56[/tex]
Hence, he has 56 choices .