Answer: 1. A) 3x−4y=10
2. [tex]y=-\frac{x}{4}+3[/tex]
3. In the attachment.
Explanation:
1. Given equation=[tex]y=\frac{3}{4}x-\frac{5}{2}[/tex]
To reduce it into standard form , multiply both sides by 4,we get
[tex]4y=4(\frac{3}{4}x-\frac{5}{2})\\\Rightarrow4y=3x-10......[distributive\ property]\\\Rightarrow3x-4y=10[/tex] which is option A.
2. Given linear equation : x+4y=12
The standard slope intercept form is given by y=mx+c where m is the slope and c is the constant.
To reduce given linear equation subtract x from both sides, we get
4y=12-x
Divide 4 on both sides.
[tex]\Rightarrow\ y=\frac{12-x}{4}=3-\frac{x}{4}\\\Rightarrow\ y=-\frac{x}{4}+3[/tex] is the slope-intercept form of the linear equation x + 4y = 12.
3. To graph equation [tex]y=\frac{1}{2}x[/tex] on the coordinate plane.
We need to find points to plot the line
Put x=0,we get y=0
Put x=2,we get y=1
Thus we have points (0,0) and (2,1) to plot the line on the graph.
