The midpoint of the line segment is [tex](\frac{-21}{2} ,5)[/tex].
Midpoint is equidistant from both endpoints, and it is the centroid both of the segment and of the endpoints.
[tex](x,y)=(\frac{x_{1}+x_{2} }{2} ,\frac{y_{1} +y_{2} }{2} )[/tex]
Where,
[tex](x, y)[/tex] is the midpoint of the line segment.
[tex](x_{1},y_{1}) and (x_{2} ,y_{2} )[/tex] are the endpoints of the line segment.
Let (x, y) be the midpoint of the line segment.
According to the given question
We have
(-8, 12) and (-13, -2) are the endpoints of the line segment.
Therefore, the midpoint of the line segment is given by
[tex](x,y)=(\frac{-8-13}{2} ,\frac{12-2}{2} )[/tex]
⇒[tex](x, y) = (\frac{-21}{2} ,\frac{10}{2})[/tex]
⇒[tex](x,y)=(\frac{-21}{2} ,5)[/tex]
Hence, the midpoint of the line segment is [tex](\frac{-21}{2} ,5)[/tex].
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