Respuesta :
3 codons code for 1 amino acid
so here you would multiply
127 x 3 = 381
So the answer is : 381
so here you would multiply
127 x 3 = 381
So the answer is : 381
The minimum number of DNA bases needed to code for ribonuclease is 381.
CODON:
- Codon refers to a sequence of three nucleotide bases that encodes an amino acid.
- The sequence of bases in the mRNA molecule is read three at a time during translation. This means that one codon (3 DNA bases) codes for one amino acid.
- Hence, if ribonuclease enzyme is 127 amino acids long, the number of DNA bases needed to encode for ribonuclease is calculated as follows:
- 1 amino acid = 3 DNA bases (codon)
- 127 amino acids = 127 × 3 = 381 DNA bases.
- Therefore, the minimum number of DNA bases needed to code for ribonuclease is 381.
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