Answer:
The number can be [tex]10\sqrt {3}[/tex]
Step-by-step explanation:
Consider the provided numbers.
We need to find a square root that lies between 17 and 18.
if x is the number
Let [tex]\sqrt x[/tex] is lies between 17 and 18
This can be written as:
[tex]17<\sqrt x<18[/tex]
[tex]289<x<324[/tex]
Take any number between 289 and 324.
Let say the number is 300
Substitute x=300 in above inequality.
[tex]289<300<324[/tex]
[tex]17^2<300<18^2[/tex]
Thus,
[tex]17<\sqrt {300}<18[/tex]
[tex]17<10\sqrt {3}<18[/tex]
Hence, the number can be [tex]10\sqrt {3}[/tex]
