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An electric fan spinning with an angular speed of 13 rad/s has a kinetic energy of 4.6 j. what is the moment of inertia of the fan?

Respuesta :

Let J = the angular moment of inertia of the fan.
The rotational speed is ω = 13 rad/s

By definition, the kinetic energy is
KE = (1/2)J*ω²

Therefore
(1/2)*(J kg-m²)*(13 rad/s)³ = 4.6 J
84.5J = 4.6
J = 0.0544 kg-m²

Answer:  J = 0.0544 kg-m²

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