The weight of the elevator is
W = (1500 kg)*(9.8 m/s²) = 1.47 x 10⁴ N
Because the frictional resistance is R = 100 N, the tension in the cable for dynamic equilibrium is
T = W + R = 1.47 x 10⁴ + 100 = 1.48 x 10⁴ N
By definition, the work done in lifting the elevator by 40 m is
(1.48 x 10⁴ N)*(40 m) = 5.92 x 10⁵ J = 592 kJ
Answer: 592 kJ (or 5.92 x 10⁵ J)
