Explanation:
It is given that mass of neon is 6.745 g and molar mass of neon is 20 g/mol.
Hence, calculate the number of moles as follows.
No. of moles = [tex]\frac{mass}{\text{molar mass}}[/tex]
Putting the given values into the above formula as follows.
No. of moles = [tex]\frac{mass}{\text{molar mass}}[/tex]
= [tex]\frac{6.745 g}{20 g/mol}[/tex]
= 0.34 mol
Also, at standard conditions value of temperature is 298 K and pressure is 1 atm.
So, putting the values into ideal gas equation and calculate the value of volume as follows.
PV = nRT
[tex]1 atm \times V = 0.34 mol \times 0.082 L atm/mol K /times 298 K[/tex]
V = 8.31 L
Thus, we can conclude that volume of given neon gas is 8.31 L.
