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Two metal balls have charges of 7.1 × 10-6 coulombs and 6.9 × 10-6 coulombs. They are 5.7 × 10-1 meters apart. What is the force of interaction between the two balls? (k = 9.0 × 109 newton·meters2/coulomb2) 5.7 newtons 6.9 newtons 7.1 newtons 1.4 newtons

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Helper10123
Hey there, Your answer wold be 1.36 newtons rounded to 1.4 newton. This is how!

force = k (q1 * q2) / r^2 

= (9.0 × 10^9 Nm^2/C^2) [(7.1 × 10^-6 C) (6.9 × 10^-6 C)] / (5.7 × 10^-1 m)^2 

= [ 9.0 × 7.1 × 6.9 / (5.7)^2 ] × 10^-1 N 

= 13.6 × 10^-1 N 

= 1.36 N

ANSWER-1.4 


HOPE I HELPED!!!!!!!!!!

Answer:

1.4

Explanation:

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