Mathematically, C’ = πd’
C’ =16, π = 22/7
∴ 16 = 22d’/7
16 x 7 = 22d’
d' = (16 x 7) / 22
d’ = 112/22
d’ = 5.09
d d’ = 0.25
d’ = 5.09
∴ d (5.09) = 0.25
d = 0.25/5.09
d = 0.05
Mathematically, C = πd
π = 22/7, d = 0.05
∴ C = 22/7 x 0.05
C = 0.16
Answer:
C = 4
Step-by-step explanation:
Given : Given a circle with measures of (C, d, and r) and a circle with measures of (C', d', and r').
and [tex]\frac{d}{d'}=0.25[/tex]
We have to find the value of C when C' = 16
Consider, The given circle with measures of (C, d, and r) and a circle with measures of (C', d', and r').
Since, Circumference of circle is directly proportional to the diameter of circle.
Thus, C ∝ d
and C' ∝ d'
Given [tex]\frac{d}{d'}=0.25[/tex]
Thus, [tex]\frac{C}{C'}=\frac{d}{d'}=0.25[/tex]
Simplify , we have,
C' = 16
[tex]\frac{C}{16}=0.25[/tex]
Simplify, we get,
[tex]C=0.25\time 16=4[/tex]
Thus, C = 4
