you roll a blue number cube and a green number cube. find P ( a number less than 2 on the blue vube and odd number on the green cube).

ON the blue cube there are 4 numbers greater than 2 and on the blue cube, 3 of the numbers are odd. As soon as BOTH outcomes have to happen (AND), you multiply the probabilities.

4/6×3/6=1/3

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MrRoyal MrRoyal · Answer 2 · 2022-05-19T10:45:40+02:00

The value of P (a number less than 2 on the blue cube and odd number on the green cube) is 1/12

How to determine the probability?

The sample space of a die is:

S = {1,2,3,4,5,6}

Using the above sample space;

The probability of getting a number less than 2 is P(x < 2) = 1/6
The probability of getting an odd number is P(Odd) = 3/6

The required probability is calculated as:

P = 1/6 * 3/6

Evaluate

P = 1/12

Hence, the value of P (a number less than 2 on the blue cube and odd number on the green cube) is 1/12