Respuesta :
we know that
A rational number is any number that can be expressed as a ratio of two integers
so
case A) [tex]12[/tex]
[tex]-\sqrt{2}*(12)=-12 \sqrt{2}[/tex] -----> is not a rational number
case B) [tex]\sqrt{2}[/tex]
[tex]-\sqrt{2}*(\sqrt{2})=-4[/tex] -----> is a rational number
because can be written as a quotient of two integer numbers. For example
[tex]-4=\frac{-8}{2}[/tex]
case C) [tex]0[/tex]
[tex]-\sqrt{2}*(0)=0[/tex] -----> is a rational number
because can be written as a quotient of two integer numbers. For example
[tex]0=\frac{0}{1}[/tex]
case D) [tex]2[/tex]
[tex]-\sqrt{2}*(2)=-2 \sqrt{2}[/tex] -----> is not a rational number
therefore
the answer is
[tex]\sqrt{2}[/tex]
[tex]0[/tex]
Every number that can be expressed as a ratio of the two numbers is a rational number, and the calculation to the points can be defined as follows:
For point A:
[tex]\to - \sqrt{2} \times 12 = - 12 \sqrt{2}[/tex] is not a rational.
For point B:
[tex]\to - \sqrt{2} \times \sqrt{2} = - 4[/tex] is a rational.
since it can be expressed as a quotient of 2 integers.
Example:
[tex]\to -4 =- \frac{8}{2}[/tex]
For point C:
[tex]\to - \sqrt{2} \times (0) =0[/tex] that is a rational.
since it can be expressed as a quotient of 2 integers.
Example:
[tex]\to 0 =\frac{0}{1}[/tex]
For point D:
[tex]\to - \sqrt{2} \times (2) = -2\sqrt{2}[/tex] that is not a rational.
Therefore, the answer is "Option B and Option C".
Learn more:
brainly.com/question/7100815