2i+3+the square root of -4. i dont understand how to write this expeession as a complex number in standard form. a step by step would be helpful! thank you!

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22-11-2017
Mathematics

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2i+3+the square root of -4. i dont understand how to write this expeession as a complex number in standard form. a step by step would be helpful! thank you!

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APAgony APAgony · Answer 1 · 2017-11-22T21:02:03+01:00

APAgony APAgony

22-11-2017

First, know that the square root of -4 can be written as 4i.
2i + 3 + 4i

Once you do that, add the 2i and 4i and you have your final answer.
6i + 3

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DragonZS DragonZS · Answer 2 · 2017-11-22T21:12:21+01:00

DragonZS DragonZS

22-11-2017

First, you would need to find the square root of -4...

So, do -4 times itself and you get 16.

Lastly, you would add the 2i, the 3, and the 16...

So the answer to this problem would be...
2i+3+16=2i+19 <==

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