[tex]\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$70.00\\
r=rate\to 16\%\to \frac{16}{100}\to &0.16\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{four times, thus}
\end{array}\to &4\\
t=years\to &25
\end{cases}
\\\\\\
A=70\left(1+\frac{0.16}{4}\right)^{4\cdot 25}\implies A=70(1.04)^{100}[/tex]
about 3500 bucks.
