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At a particular instant the location of an object relative to location a is given by the vector ra = 7, 5, 0 m. at this instant the momentum of the object is p = −10, 15, 0 kg · m/s. what is the angular momentum of the object about location a? (express your answer in vector form.)

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W0lf93
Angular momentum L is given by r X P where r is the perpendicular distance and P is the momentum. Hence our r in the equation is the distance a. So we have r=a= (7, 5, 0)/r . I had to divide by "r" because the vector appears as ra and not r, and. P = (-10, 15, 0) Taking the cross product. i (5·0 - 0·15) - j (7·0 - 0·(-10)) + k (7·15 - 5·(-10))/r = = i (0 - 0) - j (0 + 0) + k (105 + 50)/r= {0; 0; 155/r}

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