Given that,
A jar made of 3/16 inch thick glass
Radius r1 = 3.00 inches .......(1)
Height h1 = 6.00 inches .......(2)
We find r0 and h0
r0 = (3+3/16)
r0 = (3+0.1875)
r0 = 3.1875 inches .....(3)
The fomula V0 = π r0^2h0 ........(4)
h0 = (6-3/16)
h0 = (6-0.1875)
h0 = 5.8125 inches ....... (5)
The formula V1 = π r1^2h1 .........(6)
Using (4) & (6)
V = V0-V1
V = π r0^2h0 - π r1^2h1
V = π (r0^2h0 - r1^2h1)
V = π ((3.1875)^2(6) - (3)^2(5.8125))
V = π (10.16*6 - 9*5.8125)
V = π (60.96 - 52.31)
V = π (8.65)
We know that π =3.14
V = 3.14(8.65)
V = 27.17 inches^3
Therefore V = 27.17inches^3
