The angle of depression from the top of a 150 m high cliff to a boat at sea is 7 degree. How much closer to the cliff must the boat move for the angle of depression to become 19 degree.

The distance of the cliff from the boat move for the angle of depression to become 19 degree 785.84m.
If a person stands and looks down at an object, the angle of depression is the angle between the horizontal line of sight and the object.
we have,
tan 7= 150/x
0.1228= 150/x
x=150/0.1228
x= 1221.50 m
again,
tan19= 150/x
0.3443= 150/x
x=150/0.3443
x= 435.66 m
Hence, the distance of the cliff must be= 1221.50-435.66
= 785.84m closer
Learn more about angle of depression here:
https://brainly.com/question/13514202
#SPJ2