What is the approximate value of sin C?

Answer
Find the approximate value of sin C .
To proof
By using the trignometric identity
[tex]sin\theta = \frac{Perpendicular}{Hypotenuse}[/tex]
Now as given in the diagram
[tex]sin C = \frac{AB}{BC}[/tex]
as in the diagram
AB = 5 units
BC = 13.93 units
Now put it in the identity
[tex]sinC = \frac{5}{13.93}[/tex]
solving
sinC = 0.36° (approx)
Option (D) is correct
Hence proved
Answer:
(D) 0.36
Step-by-step explanation:
Given: It is given that in ΔABC, which is right angled at A has AC=13, AB=5 and BC=13.93.
To find: The value of sinC.
Solution: It is given that in ΔABC, which is right angled at A has AC=13, AB=5 and BC=13.93. thus, using the trigonometry that is:
[tex]sinC=\frac{Perpendicular}{Hypotenuse}[/tex]
[tex]sinC=\frac{AB}{BC}[/tex]
Substituting the given values, we have
[tex]sinC=\frac{5}{13.93}[/tex]
[tex]sinC=0.36[/tex]
which is the required value.
Hence, option D is correct.