Respuesta :
y=x2+2x+1-1-1 They want me write 20 characters to answer your question, lets see if this works.
Solution: The needed answer for first blank is 1 and the needed a for second blank is 1.
Explanation:
The given equation is [tex]y=x^2+2x-1[/tex].
The form of perfect square is [tex](x+y)^2=x^2+2xy+y^2[/tex].
The given equation can be written as [tex]y=(x^2+2x)-1[/tex].
To make the perfect square we can add or subtract [tex](\frac{b}{2a})^2[/tex] in the given equation. Where, a is coefficient of [tex]x^2[/tex] and b is coefficient of x. In the parenthesis the coefficient of [tex]x^2[/tex] is 1 and coefficient of x is 2.
[tex](\frac{b}{2a})^2=(\frac{2}{2(1)})^2=1[/tex]
So, the given equation is written as [tex]y=(x^2+2x+1)-1-1[/tex]
[tex]y=(x+1)^2-2[/tex]
Therefore, the needed answer for first blank is 1 and the needed a for second blank is 1.
