Answer:
Mass of [tex]3.91\times 10^{24}[/tex] number of [tex]SeO_{2}[/tex] molecules is 720.3g
Explanation:
Mass of 1 mol of [tex]SeO_{2}[/tex] is 110.96 g
We know, 1 mol of molecule = [tex]6.023\times 10^{23}[/tex] number of molecules
So, mass of [tex]6.023\times 10^{23}[/tex] number of [tex]SeO_{2}[/tex] molecules is 110.96 g
Hence mass of [tex]3.91\times 10^{24}[/tex] number of [tex]SeO_{2}[/tex] molecules = [tex]\frac{110.96\times 3.91\times 10^{24}}{6.023\times 10^{23}}g=720.3g[/tex]
