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Find 4 consecutive integers such that if the sum of the first and third is increased by 10 the result is 6 greater than 4 tiems the fourth

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the 4 consecutive integers will be x, x=1, x+2, and x+3

x+x+2+10 = 4(x+3)+6
2x+12=4x+18
-6 = 2x
x=-3
the 4 numbers are -3, -2, -1, 0

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