jennamae4142 jennamae4142

22-12-2017
Mathematics

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Find the number of real number solutions for the equation.
x^2-4x+4=0

A-1
B-0
C-cannot be determined
D-2

Respuesta :

lesliekolleroxrkcf lesliekolleroxrkcf

22-12-2017

x² - 4x + 4 = 0
(x-2)(x-2) = 0
the equation has one root mainly 2 with multiplicity 2
the answer is a

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