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A carnival has two payment options. Plan A, you pay $10 admission plus $3 for each ride. Plan B, you pay a $20 admission plus $1 for each ride. Write an inequality that would express the situation where plan B is the best buy,

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choixongdong
Let x = # of rides

Plan A: 10 + 3x

Plan B: 20 + x

if x < 5 rides then plan A is better buy
if x = 5 both plans are the same
if x > 5 then plan B is the best buy

Prove:
x = 6 (rides)

plan A: 10 + 3x = 10 + 3(6) = 10+18 = $28
plan B: 20 + x = 20 + 6 = $26

Answer:

[tex]x+20<3x+10[/tex]

Step-by-step explanation:

Let x represent the number of rides.

We have been given that a carnival has two payment options.

In Plan A, you pay $10 admission plus $3 for each ride. The total cost for x rides using plan A would be [tex]3x+10[/tex].

In Plan B, you pay a $20 admission plus $1 for each ride.The total cost for x rides using plan B would be [tex]x+20[/tex].

Now we will show that plan B is best buy by showing that cost of x rides in plan B is less than plan A as:

[tex]x+20<3x+10[/tex]

Therefore, our required inequality would be [tex]x+20<3x+10[/tex].

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