The growth of a bug population shows a geometric sequence as shown in the table. This pattern continues indefinitely. What will the population be on Week 20?

♦about 1,496,366
♦about 997,577
♦about 665,051
♦about 464,758

The growth of a bug population shows a geometric sequence as shown in the table This pattern continues indefinitely What will the population be on Week 20 about class=

Respuesta :

The common ratio is,
r= 450/300 = 3/2


nth term of geometric series is given by,
a[tex] _{n} [/tex] = a₁r[tex] ^{n-1} [/tex]
a₂₀ = 300(3/2)¹⁹ = 665051

Answer:

the population be on Week 20 is about 665,051

Step-by-step explanation:

The growth of a bug population shows a geometric sequence as shown in the table

For all geometric sequence , there should be a common ratio

Lets find common ratio 'r'

To find common ratio we divide second term by first term

so common ratio [tex]r= \frac{450}{300} =\frac{3}{2}[/tex]

To find nth term of geometric sequence , formula is

[tex]a_n = a_1(r)^{n-1}[/tex]

Where a1 is the first term  and r is the common difference

a1= 300 and r= 3/2

We need to find the population on Week 20, so n= 20

We plug in all the values and find out a20

[tex]a_{20} = 300(\frac{3}{2})^{20-1}[/tex]

[tex]a_{20} = 300(\frac{3}{2})^{19}=300*2216.83782=665051.346[/tex]

the population be on Week 20 is about 665,051