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Given that the domain is all real numbers, what is the limit of the range for the function ƒ(x) = 4^2x - 100?

Respuesta :

[ -100, ∞ ). as X decreases f of x approaches -100 asymptotically as X increases f of x increases without bound

Answer:

The limit of the range is y>-100.

Step-by-step explanation:

Given : The domain is all real numbers, for the function [tex]f(x) = 4^{2x} - 100[/tex]

To find : what is the limit of the range for the function?

Solution :

The function we have given is an exponential function.

The domain of the function [tex]f(x) = 4^{2x} - 100[/tex]  is all real number.

i.e, [tex]D=(-\infty,\infty),[x|x\in\mathbb{R}][/tex]

Range is defined as the set of value that corresponds with the domain.

Taking, [tex]x\rightarrow\infty[/tex]

Function approaches to -100

Taking, [tex]x\rightarrow -\infty[/tex]

Function approaches to [tex]\infty[/tex]

Therefore, The range of the function is defined as

[tex]R=(-100,\infty),[y|y>-100][/tex]

So, The limit of the range is y>-100.