Respuesta :
Explanation:
According to the mole concept there are [tex]6.022 \times 10^{23} atoms[/tex] present in 1 mole of a substance.
Mathematically, 1 mole = [tex]6.022 \times 10^{23}[/tex] atoms or molecules
Therefore, number of moles present in 76.8 g of [tex]CO_{2}[/tex] are as follows.
No. of moles = [tex]\frac{mass}{\text{molar mass}}[/tex]
= [tex]\frac{76.8 g}{44 g/mol}[/tex]
= 1.74 mol
As there are two atoms of oxygen are present in a molecule of [tex]CO_{2}[/tex]. Hence, calculate the number of oxygen atoms present in 1.74 mol of [tex]CO_{2}[/tex] as follows.
[tex]2 \times 1.74 mol \times 6.022 \times 10^{23}}atoms /mol[/tex]
= [tex]20.95 \times 10^{23}[/tex] atoms
Thus, we can conclude that there are [tex]20.95 \times 10^{23}[/tex] atoms of oxygen are present in 76.8g of [tex]CO_{2}[/tex].