Respuesta :

I think it would 55.8 grams but i could be wrong

Explanation:

According to the mole concept there are [tex]6.022 \times 10^{23} atoms[/tex] present in 1 mole of a substance.

Mathematically,    1 mole = [tex]6.022 \times 10^{23}[/tex] atoms or molecules

Therefore, number of moles present in 76.8 g of [tex]CO_{2}[/tex] are as follows.

               No. of moles = [tex]\frac{mass}{\text{molar mass}}[/tex]

                                      = [tex]\frac{76.8 g}{44 g/mol}[/tex]

                                      = 1.74 mol

As there are two atoms of oxygen are present in a molecule of [tex]CO_{2}[/tex]. Hence, calculate the number of oxygen atoms present in 1.74 mol of [tex]CO_{2}[/tex] as follows.

            [tex]2 \times 1.74 mol \times 6.022 \times 10^{23}}atoms /mol[/tex]

                 = [tex]20.95 \times 10^{23}[/tex] atoms

Thus, we can conclude that there are [tex]20.95 \times 10^{23}[/tex] atoms of oxygen are present in 76.8g of [tex]CO_{2}[/tex].