The length of a rectangular sign is 5 times its width. If the sign’s perimeter is 36 inches, what is the sign’s area?

As the length of the sign is 5 times its width and the perimeter is 36.

The width of the rectangular sign is equal 30 and the length 6.

By multiplying 30 times 6, you would find out that the answer for the area of the rectangular sign is 180 inches.

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abidemiokin abidemiokin · Answer 2 · 2021-10-04T12:00:47+02:00

The area of the sign is 45 square inches

The formula for finding the perimeter of a rectangle is expressed as:

[tex]P=2(L+W)[/tex]

L is the length

W is the width

If the length of a rectangular sign is 5 times its width, hence;

L = 5W

Perimeter = 36in

Substitute the given parameter into the formula

[tex]36=2(5W+W)\\36=2(6W)\\36=12W\\W=\frac{36}{12}\\W=3in[/tex]

The area of the sign is expressed as:

[tex]A = LW\\A=5(W)(W)\\A=5w^2\\A=5(3)^2\\a=45in^2[/tex]

Hence the area of the sign is 45 square inches

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