Dénote l the vertical leap, then the given equation can be written like this:
[tex]l(t)=4t^2\\\text{Since one inch equate 0.0833333 feet then 44 inches equate }\\44\times 0.0833333=3.6feet\\\text{Add to 33 feet like this:}\\33+3.6=36.6feet\\\text{Now we have to solve the equation:}\\4t^2=36.6\\\text{Divide over 4 we get:}\\t^2= \frac{36.6}{4}=9.15\\\text{Take the square root we get:}\\t=\sqrt{9.15}=3 [/tex]
The hang time equates then 3 seconds
