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A case of 24 vegetable cans has 1 that is contaminated. 3 cans are to be chosen at random for testing.
a. How many different combinations of 3 cans are there?
b. What is the probability that the contaminated can is selected for testing with any given set of 3 cans?

Respuesta :

bobeld
How many ways can we pick 3 thing out of a field of 24 if the order does not matter.    24C3  means   24 x 23 x 22 divided by 3 x 2 x 1 or 6  


24 x 23 x 22
3!  (3 x 2 x 1)

12,144 /6 = 2,024 combinations of 3 cans.
 
The probability that you have the contaminated can in any of those 3 can combinations is 1 in 2,024 or 1/,024

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