Respuesta :
Question #1
Part A:
The y-intercept can be found when x = 0. If you look at your table, when x = 0, y = 5. So the y-intercept is 5.
Part B:
[tex]\sf Slope = \frac{27-5}{1-0} = \frac{22}{1} = \boxed{22}[/tex]
The slope is 22.
Part C:
y = mx + b
y = 22x + 5
We are given 225 as the range, or in place of y.
225 = 22x + 5
220 = 22x
x = 10
The domain is 10.
Question #2
Part A:
(2,255)
(5,480)
Standard form is Ax + By = C
[tex]\sf Slope = \frac{y_2-y_1}{x_2-x_1} = \frac{480-225}{5-2} = \frac{255}{3} = \boxed{85}[/tex]
Let's plug this into this form first:
[tex]y - y_1 = m(x-x_1)\\\\y -225 = 85(x-2)\\\\y - 225 = 85x - 170\\\\y = 85x + 55[/tex]
Now, let's make it into Standard Form.
[tex]y = 85x + 55\\\\y - 85x + 55\\\\ -85x + y = 55\\\\ -1(-85x +y) = -1(55)\\\\\boxed{85x - y = -55}[/tex]
What, which is in the box, is your final answer. :)
Part B:
Function notation simply means replacing y with f(x).
We had y = 85x + 55
So your answer is:
[tex]\boxed{f(x) = 85x + 55}[/tex]
Part C:
Using the final answer which we got in Part A, we would know that the y-intercept is (0,55) and the x-intercept is (-55/85, 0). We would plot these 2 points, and then draw a line between them. :)
Part A:
The y-intercept can be found when x = 0. If you look at your table, when x = 0, y = 5. So the y-intercept is 5.
Part B:
[tex]\sf Slope = \frac{27-5}{1-0} = \frac{22}{1} = \boxed{22}[/tex]
The slope is 22.
Part C:
y = mx + b
y = 22x + 5
We are given 225 as the range, or in place of y.
225 = 22x + 5
220 = 22x
x = 10
The domain is 10.
Question #2
Part A:
(2,255)
(5,480)
Standard form is Ax + By = C
[tex]\sf Slope = \frac{y_2-y_1}{x_2-x_1} = \frac{480-225}{5-2} = \frac{255}{3} = \boxed{85}[/tex]
Let's plug this into this form first:
[tex]y - y_1 = m(x-x_1)\\\\y -225 = 85(x-2)\\\\y - 225 = 85x - 170\\\\y = 85x + 55[/tex]
Now, let's make it into Standard Form.
[tex]y = 85x + 55\\\\y - 85x + 55\\\\ -85x + y = 55\\\\ -1(-85x +y) = -1(55)\\\\\boxed{85x - y = -55}[/tex]
What, which is in the box, is your final answer. :)
Part B:
Function notation simply means replacing y with f(x).
We had y = 85x + 55
So your answer is:
[tex]\boxed{f(x) = 85x + 55}[/tex]
Part C:
Using the final answer which we got in Part A, we would know that the y-intercept is (0,55) and the x-intercept is (-55/85, 0). We would plot these 2 points, and then draw a line between them. :)