Respuesta :
the answer is 10,270. 3/5 of 49,080 is 29448 and 15% of 49,080 is 7362. 29448+7362 is 36810 and 49080-36810=10270.
Answer: The required number of tickets sold for the semi-final matches is 12270.
Step-by-step explanation: Given that 49080 tickets have been sold for the tournament. [tex]\dfrac{3}{5}[/tex] of the tickets are for the qualifying matches and 15% of the tickets are for the final match.
We are to find the number of tickets that sold for the semi-final matches.
Let s denotes the number of tickets that are sold for semi final matches.
According to the given information, we have
Number of tickets sold for the qualifying matches is
[tex]n_q=\dfrac{3}{5}\times49080=29448[/tex]
and the number of tickets sold for the final match is
[tex]n_f=15\%\times49080=\dfrac{15}{100}\times49080=7362.[/tex]
Therefore, we must have
[tex]n_q+n_f+s=49080\\\\\Rightarrow 29448+7362+s=49080\\\\\Rightarrow 36810+s=49080\\\\\Rightarrow s=49080-36810\\\\\Rightarrow s=12270.[/tex]
Thus, the required number of tickets sold for the semi-final matches is 12270.
